What are the solutions to the equation -4(x-1)^2+28=-100 ?

The solutions to the equation -4(x-1)^2+28=-100 are x=4sqrt(2)+1,x=-4sqrt(2)+1

Find the zeros of -4(x-1)^2+28=-100

The zeros of -4(x-1)^2+28=-100 are x=4sqrt(2)+1,x=-4sqrt(2)+1

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- 4 (x - 1)^{2} + 28 = - 100

x = 42 + 1, x = - 42 + 1

Decimal Notation

x = 6.65685 \dots, x = - 4.65685 \dots

Solution steps

- 4 (x - 1)^{2} + 28 = - 100

Move

28

to the right side

- 4 (x - 1)^{2} = - 128

Divide both sides by

- 4

(x - 1)^{2} = 32

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = 32 : x = 42 + 1

Solve

x - 1 = - 32 : x = - 42 + 1

The solutions to the quadratic equation are:

x = 42 + 1, x = - 42 + 1

4 d^{2} + 9 = 12 d

2 p^{2} = 0

x^{2} - 20 x - 1500 = 0

8 x^{2} + 4 x - 7 = 0

3 x^{2} + 3 - 6 = 0

What are the solutions to the equation -4(x-1)^2+28=-100 ?
The solutions to the equation -4(x-1)^2+28=-100 are x=4sqrt(2)+1,x=-4sqrt(2)+1
Find the zeros of -4(x-1)^2+28=-100
The zeros of -4(x-1)^2+28=-100 are x=4sqrt(2)+1,x=-4sqrt(2)+1