What are the solutions to the equation 4d^2+9=12d ?

The solutions to the equation 4d^2+9=12d are d= 3/2

Find the zeros of 4d^2+9=12d

The zeros of 4d^2+9=12d are d= 3/2

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4 d^{2} + 9 = 12 d

d = \frac{3}{2}

Decimal

d = 1.5

Solution steps

4 d^{2} + 9 = 12 d

Move

12 d

to the left side

4 d^{2} + 9 - 12 d = 0

Write in the standard form

a x^{2} + b x + c = 0

4 d^{2} - 12 d + 9 = 0

Solve with the quadratic formula

d_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 9 = 0

d_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 4}

d = \frac{- ( - 12 )}{2 \cdot 4}

\frac{- ( - 12 )}{2 \cdot 4} = \frac{3}{2}

d = \frac{3}{2}

The solution to the quadratic equation is:

d = \frac{3}{2}

2 p^{2} = 0

x^{2} - 20 x - 1500 = 0

8 x^{2} + 4 x - 7 = 0

3 x^{2} + 3 - 6 = 0

2 x^{2} + 20 x - 24 = 0

What are the solutions to the equation 4d^2+9=12d ?
The solutions to the equation 4d^2+9=12d are d= 3/2
Find the zeros of 4d^2+9=12d
The zeros of 4d^2+9=12d are d= 3/2