What are the solutions to the equation 2x^2+20x-24=0 ?

The solutions to the equation 2x^2+20x-24=0 are x=-5+sqrt(37),x=-5-sqrt(37)

Find the zeros of 2x^2+20x-24=0

The zeros of 2x^2+20x-24=0 are x=-5+sqrt(37),x=-5-sqrt(37)

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2 x^{2} + 20 x - 24 = 0

x = - 5 + 37, x = - 5 - 37

Decimal Notation

x = 1.08276 \dots, x = - 11.08276 \dots

Solution steps

2 x^{2} + 20 x - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 2 ( - 24 )}{2 \cdot 2}

2 0^{2} - 4 \cdot 2 (- 24) = 437

x_{1, 2} = \frac{- 20 \pm 4 37}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 20 + 4 37}{2 \cdot 2}, x_{2} = \frac{- 20 - 4 37}{2 \cdot 2}

x = \frac{- 20 + 4 37}{2 \cdot 2} : - 5 + 37

x = \frac{- 20 - 4 37}{2 \cdot 2} : - 5 - 37

The solutions to the quadratic equation are:

x = - 5 + 37, x = - 5 - 37

4 x^{2} - 11 x - 7 = 0

33 x - 2 = (3 x + 2)^{2}

(x + 4)^{2} = (x + 2)^{2} + x^{2}

3 z^{2} - 12 z

5 x^{2} + 32 x - 21 = 0

What are the solutions to the equation 2x^2+20x-24=0 ?
The solutions to the equation 2x^2+20x-24=0 are x=-5+sqrt(37),x=-5-sqrt(37)
Find the zeros of 2x^2+20x-24=0
The zeros of 2x^2+20x-24=0 are x=-5+sqrt(37),x=-5-sqrt(37)