What are the solutions to the equation 5x^2+32x-21=0 ?

The solutions to the equation 5x^2+32x-21=0 are x= 3/5 ,x=-7

Find the zeros of 5x^2+32x-21=0

The zeros of 5x^2+32x-21=0 are x= 3/5 ,x=-7

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5 x^{2} + 32 x - 21 = 0

x = \frac{3}{5}, x = - 7

Decimal Notation

x = 0.6, x = - 7

Solution steps

5 x^{2} + 32 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 32 \pm 3 2 ^{2} - 4 \cdot 5 ( - 21 )}{2 \cdot 5}

3 2^{2} - 4 \cdot 5 (- 21) = 38

x_{1, 2} = \frac{- 32 \pm 38}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 32 + 38}{2 \cdot 5}, x_{2} = \frac{- 32 - 38}{2 \cdot 5}

x = \frac{- 32 + 38}{2 \cdot 5} : \frac{3}{5}

x = \frac{- 32 - 38}{2 \cdot 5} : - 7

The solutions to the quadratic equation are:

x = \frac{3}{5}, x = - 7

q^{2} - 140 q + 4800 = 0

x^{2} + x = 210

x^{2} + 3 x = 2 (x - 1)

0 = y (4 - y)

x, f (h (x)) = x^{2} + 7

What are the solutions to the equation 5x^2+32x-21=0 ?
The solutions to the equation 5x^2+32x-21=0 are x= 3/5 ,x=-7
Find the zeros of 5x^2+32x-21=0
The zeros of 5x^2+32x-21=0 are x= 3/5 ,x=-7