What are the solutions to the equation x^2+x=210 ?

The solutions to the equation x^2+x=210 are x=14,x=-15

Find the zeros of x^2+x=210

The zeros of x^2+x=210 are x=14,x=-15

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x^{2} + x = 210

x = 14, x = - 15

Solution steps

x^{2} + x = 210

Move

210

to the left side

x^{2} + x - 210 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot ( - 210 )}{2 \cdot 1}

1^{2} - 4 \cdot 1 \cdot (- 210) = 29

x_{1, 2} = \frac{- 1 \pm 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 29}{2 \cdot 1}, x_{2} = \frac{- 1 - 29}{2 \cdot 1}

x = \frac{- 1 + 29}{2 \cdot 1} : 14

x = \frac{- 1 - 29}{2 \cdot 1} : - 15

The solutions to the quadratic equation are:

x = 14, x = - 15

x^{2} + 3 x = 2 (x - 1)

0 = y (4 - y)

x, f (h (x)) = x^{2} + 7

x^{2} = 1^{2} + 4^{2}

2 x^{2} + 5 x - 8 = 0

What are the solutions to the equation x^2+x=210 ?
The solutions to the equation x^2+x=210 are x=14,x=-15
Find the zeros of x^2+x=210
The zeros of x^2+x=210 are x=14,x=-15