What are the solutions to the equation -81v^2+91=21 ?

The solutions to the equation -81v^2+91=21 are v=(sqrt(70))/9 ,v=-(sqrt(70))/9

Find the zeros of -81v^2+91=21

The zeros of -81v^2+91=21 are v=(sqrt(70))/9 ,v=-(sqrt(70))/9

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- 81 v^{2} + 91 = 21

v = \frac{70}{9}, v = - \frac{70}{9}

Decimal Notation

v = 0.92962 \dots, v = - 0.92962 \dots

Solution steps

- 81 v^{2} + 91 = 21

Move

91

to the right side

- 81 v^{2} = - 70

Divide both sides by

- 81

v^{2} = \frac{70}{81}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = \frac{70}{81}, v = - \frac{70}{81}

\frac{70}{81} = \frac{70}{9}

- \frac{70}{81} = - \frac{70}{9}

v = \frac{70}{9}, v = - \frac{70}{9}

4 a^{2} - 16 a + 16 = 36 a - 144

4 x^{2} = 27 x + 7

20 = - 16 t^{2} + 100 t + 5

4 w (w + 3) + 15 = 0

- 4 x^{2} + 64 x - 252 = 0

What are the solutions to the equation -81v^2+91=21 ?
The solutions to the equation -81v^2+91=21 are v=(sqrt(70))/9 ,v=-(sqrt(70))/9
Find the zeros of -81v^2+91=21
The zeros of -81v^2+91=21 are v=(sqrt(70))/9 ,v=-(sqrt(70))/9