What are the solutions to the equation x^2-12x-81=-9 ?

The solutions to the equation x^2-12x-81=-9 are x=6(1+sqrt(3)),x=6(1-sqrt(3))

Find the zeros of x^2-12x-81=-9

The zeros of x^2-12x-81=-9 are x=6(1+sqrt(3)),x=6(1-sqrt(3))

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x^{2} - 12 x - 81 = - 9

x = 6 (1 + 3), x = 6 (1 - 3)

Decimal Notation

x = 16.39230 \dots, x = - 4.39230 \dots

Solution steps

x^{2} - 12 x - 81 = - 9

Move

9

to the left side

x^{2} - 12 x - 72 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 72 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 72) = 123

x_{1, 2} = \frac{- ( - 12 ) \pm 12 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 12 3}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 12 3}{2 \cdot 1}

x = \frac{- ( - 12 ) + 12 3}{2 \cdot 1} : 6 (1 + 3)

x = \frac{- ( - 12 ) - 12 3}{2 \cdot 1} : 6 (1 - 3)

The solutions to the quadratic equation are:

x = 6 (1 + 3), x = 6 (1 - 3)

7 x^{2} = 2 x + 6

x^{2} - 8 x + 32 = 12 x - 4

- 5 x^{2} + 525 x - 2500 = 0

27 = 3 x^{2} + 12 x

x^{2} + 20 = 24

What are the solutions to the equation x^2-12x-81=-9 ?
The solutions to the equation x^2-12x-81=-9 are x=6(1+sqrt(3)),x=6(1-sqrt(3))
Find the zeros of x^2-12x-81=-9
The zeros of x^2-12x-81=-9 are x=6(1+sqrt(3)),x=6(1-sqrt(3))