What are the solutions to the equation 27=3x^2+12x ?

The solutions to the equation 27=3x^2+12x are x=-2+sqrt(13),x=-2-sqrt(13)

Find the zeros of 27=3x^2+12x

The zeros of 27=3x^2+12x are x=-2+sqrt(13),x=-2-sqrt(13)

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27 = 3 x^{2} + 12 x

x = - 2 + 13, x = - 2 - 13

Decimal Notation

x = 1.60555 \dots, x = - 5.60555 \dots

Solution steps

27 = 3 x^{2} + 12 x

Switch sides

3 x^{2} + 12 x = 27

Move

27

to the left side

3 x^{2} + 12 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 3 ( - 27 )}{2 \cdot 3}

1 2^{2} - 4 \cdot 3 (- 27) = 613

x_{1, 2} = \frac{- 12 \pm 6 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 12 + 6 13}{2 \cdot 3}, x_{2} = \frac{- 12 - 6 13}{2 \cdot 3}

x = \frac{- 12 + 6 13}{2 \cdot 3} : - 2 + 13

x = \frac{- 12 - 6 13}{2 \cdot 3} : - 2 - 13

The solutions to the quadratic equation are:

x = - 2 + 13, x = - 2 - 13

x^{2} + 20 = 24

x, y = (x - 3)^{2} - 4

x, y^{4} + 7 x y^{2} = x^{2}

y, x = (y - 1)^{2} - 2

x^{2} - 3.5 x = 0

What are the solutions to the equation 27=3x^2+12x ?
The solutions to the equation 27=3x^2+12x are x=-2+sqrt(13),x=-2-sqrt(13)
Find the zeros of 27=3x^2+12x
The zeros of 27=3x^2+12x are x=-2+sqrt(13),x=-2-sqrt(13)