What are the solutions to the equation solvefor y,x=(y-1)^2-2 ?

The solutions to the equation solvefor y,x=(y-1)^2-2 are y=sqrt(x+2)+1,y=-sqrt(x+2)+1

Find the zeros of solvefor y,x=(y-1)^2-2

The zeros of solvefor y,x=(y-1)^2-2 are y=sqrt(x+2)+1,y=-sqrt(x+2)+1

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solve for

y, x = (y - 1)^{2} - 2

y = x + 2 + 1, y = - x + 2 + 1

Solution steps

x = (y - 1)^{2} - 2

Switch sides

(y - 1)^{2} - 2 = x

Move

2

to the right side

(y - 1)^{2} = x + 2

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

y - 1 = x + 2 : y = x + 2 + 1

Solve

y - 1 = - x + 2 : y = - x + 2 + 1

The solutions to the quadratic equation are:

y = x + 2 + 1, y = - x + 2 + 1

x^{2} - 3.5 x = 0

4 x^{2} - 12 x - 280 = 0

3 x^{2} + x - 4 = 0

8 x = 4 (x^{2} + 2 x)

x^{2} - 2 x + 82

What are the solutions to the equation solvefor y,x=(y-1)^2-2 ?
The solutions to the equation solvefor y,x=(y-1)^2-2 are y=sqrt(x+2)+1,y=-sqrt(x+2)+1
Find the zeros of solvefor y,x=(y-1)^2-2
The zeros of solvefor y,x=(y-1)^2-2 are y=sqrt(x+2)+1,y=-sqrt(x+2)+1