What are the solutions to the equation factor 3x^2+x-4=0 ?

The solutions to the equation factor 3x^2+x-4=0 are x=1,x=-4/3

Find the zeros of factor 3x^2+x-4=0

The zeros of factor 3x^2+x-4=0 are x=1,x=-4/3

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3 x^{2} + x - 4 = 0

x = 1, x = - \frac{4}{3}

Decimal Notation

x = 1, x = - 1.33333 \dots

Solution steps

3 x^{2} + x - 4 = 0

Factor

3 x^{2} + x - 4 : (x - 1) (3 x + 4)

(x - 1) (3 x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 3 x + 4 = 0

Solve

x - 1 = 0 : x = 1

Solve

3 x + 4 = 0 : x = - \frac{4}{3}

The solutions to the quadratic equation are:

x = 1, x = - \frac{4}{3}

8 x = 4 (x^{2} + 2 x)

x^{2} - 2 x + 82

- 3 x^{2} - 5 x = - 1

x, f (x + 1) = 3 x^{2} - x + 2

5 x = - 8 x^{2} + 10

What are the solutions to the equation factor 3x^2+x-4=0 ?
The solutions to the equation factor 3x^2+x-4=0 are x=1,x=-4/3
Find the zeros of factor 3x^2+x-4=0
The zeros of factor 3x^2+x-4=0 are x=1,x=-4/3