What are the solutions to the equation 0=168pix-6pi^2x^2 ?

The solutions to the equation 0=168pix-6pi^2x^2 are x=0,x=(28)/pi

Find the zeros of 0=168pix-6pi^2x^2

The zeros of 0=168pix-6pi^2x^2 are x=0,x=(28)/pi

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0 = 168 π x - 6 π^{2} x^{2}

x = 0, x = \frac{28}{π}

Decimal Notation

x = 0, x = 8.91267 \dots

Solution steps

0 = 168 π x - 6 π^{2} x^{2}

Switch sides

168 π x - 6 π^{2} x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- 6 π^{2} x^{2} + 168 π x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 168 π \pm ( 168 π ) ^{2} - 4 ( - 6 π ^{2} ) \cdot 0}{2 ( - 6 π ^{2} )}

(168 π)^{2} - 4 (- 6 π^{2}) \cdot 0 = 168 π

x_{1, 2} = \frac{- 168 π \pm 168 π}{2 ( - 6 π ^{2} )}

Separate the solutions

x_{1} = \frac{- 168 π + 168 π}{2 ( - 6 π ^{2} )}, x_{2} = \frac{- 168 π - 168 π}{2 ( - 6 π ^{2} )}

x = \frac{- 168 π + 168 π}{2 ( - 6 π ^{2} )} : 0

x = \frac{- 168 π - 168 π}{2 ( - 6 π ^{2} )} : \frac{28}{π}

The solutions to the quadratic equation are:

x = 0, x = \frac{28}{π}

x, x^{2} + x y = 0

- x^{2} + x + 1 = 0

x \frac{3 x - 8}{5} = - 4

6 y^{2} + 2 y - 1 = 0

6 x^{2} + 1 = 10 x

What are the solutions to the equation 0=168pix-6pi^2x^2 ?
The solutions to the equation 0=168pix-6pi^2x^2 are x=0,x=(28)/pi
Find the zeros of 0=168pix-6pi^2x^2
The zeros of 0=168pix-6pi^2x^2 are x=0,x=(28)/pi