What are the solutions to the equation 3m^2-4=m ?

The solutions to the equation 3m^2-4=m are m= 4/3 ,m=-1

Find the zeros of 3m^2-4=m

The zeros of 3m^2-4=m are m= 4/3 ,m=-1

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3 m^{2} - 4 = m

m = \frac{4}{3}, m = - 1

Decimal Notation

m = 1.33333 \dots, m = - 1

Solution steps

3 m^{2} - 4 = m

Move

m

to the left side

3 m^{2} - 4 - m = 0

Write in the standard form

a x^{2} + b x + c = 0

3 m^{2} - m - 4 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 3 ( - 4 )}{2 \cdot 3}

(- 1)^{2} - 4 \cdot 3 (- 4) = 7

m_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 3}

Separate the solutions

m_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 3}, m_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 3}

m = \frac{- ( - 1 ) + 7}{2 \cdot 3} : \frac{4}{3}

m = \frac{- ( - 1 ) - 7}{2 \cdot 3} : - 1

The solutions to the quadratic equation are:

m = \frac{4}{3}, m = - 1

2 m^{2} + 13 m - 7 = 0

x^{2} + x = x

9 + 5 x - x^{2}

(2 x - 7) (3 x - 5) = 0

x, x^{2} (y + 4)^{2} = 25

What are the solutions to the equation 3m^2-4=m ?
The solutions to the equation 3m^2-4=m are m= 4/3 ,m=-1
Find the zeros of 3m^2-4=m
The zeros of 3m^2-4=m are m= 4/3 ,m=-1