What are the solutions to the equation 16x+x^2=14+13x-x^2 ?

The solutions to the equation 16x+x^2=14+13x-x^2 are x=-7/2 ,x=2

Find the zeros of 16x+x^2=14+13x-x^2

The zeros of 16x+x^2=14+13x-x^2 are x=-7/2 ,x=2

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16 x + x^{2} = 14 + 13 x - x^{2}

x = - \frac{7}{2}, x = 2

Decimal Notation

x = - 3.5, x = 2

Solution steps

16 x + x^{2} = 14 + 13 x - x^{2}

Switch sides

14 + 13 x - x^{2} = 16 x + x^{2}

Move

x^{2}

to the left side

14 + 13 x - 2 x^{2} = 16 x

Move

16 x

to the left side

- 2 x^{2} - 3 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 ( - 2 ) \cdot 14}{2 ( - 2 )}

(- 3)^{2} - 4 (- 2) \cdot 14 = 11

x_{1, 2} = \frac{- ( - 3 ) \pm 11}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 11}{2 ( - 2 )}, x_{2} = \frac{- ( - 3 ) - 11}{2 ( - 2 )}

x = \frac{- ( - 3 ) + 11}{2 ( - 2 )} : - \frac{7}{2}

x = \frac{- ( - 3 ) - 11}{2 ( - 2 )} : 2

The solutions to the quadratic equation are:

x = - \frac{7}{2}, x = 2

5 a^{2} - 7 + 1 = 1.2

x^{2} - 6 + x = 0

x^{2} + 3 x = x

6 n^{2} + 12 n - 38 = 0

- 5 x^{2} - 60 x - 100 = 0

What are the solutions to the equation 16x+x^2=14+13x-x^2 ?
The solutions to the equation 16x+x^2=14+13x-x^2 are x=-7/2 ,x=2
Find the zeros of 16x+x^2=14+13x-x^2
The zeros of 16x+x^2=14+13x-x^2 are x=-7/2 ,x=2