What are the solutions to the equation 150=20+26x-2x^2 ?

The solutions to the equation 150=20+26x-2x^2 are x= 13/2-i(sqrt(91))/2 ,x= 13/2+i(sqrt(91))/2

Find the zeros of 150=20+26x-2x^2

The zeros of 150=20+26x-2x^2 are x= 13/2-i(sqrt(91))/2 ,x= 13/2+i(sqrt(91))/2

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150 = 20 + 26 x - 2 x^{2}

x = \frac{13}{2} - i \frac{91}{2}, x = \frac{13}{2} + i \frac{91}{2}

Solution steps

150 = 20 + 26 x - 2 x^{2}

Switch sides

20 + 26 x - 2 x^{2} = 150

Move

150

to the left side

- 2 x^{2} + 26 x - 130 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 ( - 2 ) ( - 130 )}{2 ( - 2 )}

Simplify

2 6^{2} - 4 (- 2) (- 130) : 291 i

x_{1, 2} = \frac{- 26 \pm 2 91 i}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 26 + 2 91 i}{2 ( - 2 )}, x_{2} = \frac{- 26 - 2 91 i}{2 ( - 2 )}

x = \frac{- 26 + 2 91 i}{2 ( - 2 )} : \frac{13}{2} - i \frac{91}{2}

x = \frac{- 26 - 2 91 i}{2 ( - 2 )} : \frac{13}{2} + i \frac{91}{2}

The solutions to the quadratic equation are:

x = \frac{13}{2} - i \frac{91}{2}, x = \frac{13}{2} + i \frac{91}{2}

12 x^{2} + 8 = 20 x

120 x^{2} - 54 x - 27 = 0

x^{2} + 11 x + 1 = 0

y^{2} - 12 y + 25 = 0

- 0.018 q^{2} - 12 q + 510 = 0

What are the solutions to the equation 150=20+26x-2x^2 ?
The solutions to the equation 150=20+26x-2x^2 are x= 13/2-i(sqrt(91))/2 ,x= 13/2+i(sqrt(91))/2
Find the zeros of 150=20+26x-2x^2
The zeros of 150=20+26x-2x^2 are x= 13/2-i(sqrt(91))/2 ,x= 13/2+i(sqrt(91))/2