What are the solutions to the equation 4r^2+3r+6=357 ?

The solutions to the equation 4r^2+3r+6=357 are r=9,r=-39/4

Find the zeros of 4r^2+3r+6=357

The zeros of 4r^2+3r+6=357 are r=9,r=-39/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 r^{2} + 3 r + 6 = 357

r = 9, r = - \frac{39}{4}

Decimal Notation

r = 9, r = - 9.75

Solution steps

4 r^{2} + 3 r + 6 = 357

Move

357

to the left side

4 r^{2} + 3 r - 351 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 \cdot 4 ( - 351 )}{2 \cdot 4}

3^{2} - 4 \cdot 4 (- 351) = 75

r_{1, 2} = \frac{- 3 \pm 75}{2 \cdot 4}

Separate the solutions

r_{1} = \frac{- 3 + 75}{2 \cdot 4}, r_{2} = \frac{- 3 - 75}{2 \cdot 4}

r = \frac{- 3 + 75}{2 \cdot 4} : 9

r = \frac{- 3 - 75}{2 \cdot 4} : - \frac{39}{4}

The solutions to the quadratic equation are:

r = 9, r = - \frac{39}{4}

144 x^{2} - 9 = 0

0 = x^{2} + 5 x - 14

x^{2} = 12 x - 32

y, s (y) = 5 yy + 7

1 - 4 x - 2 x^{2}

What are the solutions to the equation 4r^2+3r+6=357 ?
The solutions to the equation 4r^2+3r+6=357 are r=9,r=-39/4
Find the zeros of 4r^2+3r+6=357
The zeros of 4r^2+3r+6=357 are r=9,r=-39/4