What are the solutions to the equation x^2-20x-12=-3 ?

The solutions to the equation x^2-20x-12=-3 are x=10+sqrt(109),x=10-sqrt(109)

Find the zeros of x^2-20x-12=-3

The zeros of x^2-20x-12=-3 are x=10+sqrt(109),x=10-sqrt(109)

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x^{2} - 20 x - 12 = - 3

x = 10 + 109, x = 10 - 109

Decimal Notation

x = 20.44030 \dots, x = - 0.44030 \dots

Solution steps

x^{2} - 20 x - 12 = - 3

Move

3

to the left side

x^{2} - 20 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

(- 20)^{2} - 4 \cdot 1 \cdot (- 9) = 2109

x_{1, 2} = \frac{- ( - 20 ) \pm 2 109}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 20 ) + 2 109}{2 \cdot 1}, x_{2} = \frac{- ( - 20 ) - 2 109}{2 \cdot 1}

x = \frac{- ( - 20 ) + 2 109}{2 \cdot 1} : 10 + 109

x = \frac{- ( - 20 ) - 2 109}{2 \cdot 1} : 10 - 109

The solutions to the quadratic equation are:

x = 10 + 109, x = 10 - 109

4 x^{2} + 32 x

4 x^{2} = 9 x + 28

x^{2} + 3 x + 8 = 0

6 x^{(2)} + 5 = 17 x

a, a^{2} b + c = 24

What are the solutions to the equation x^2-20x-12=-3 ?
The solutions to the equation x^2-20x-12=-3 are x=10+sqrt(109),x=10-sqrt(109)
Find the zeros of x^2-20x-12=-3
The zeros of x^2-20x-12=-3 are x=10+sqrt(109),x=10-sqrt(109)