What is factor 9p^2+6p+1-q^2 ?

The solution to factor 9p^2+6p+1-q^2 is (3p+1+q)(3p+1-q)

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factor 9p^2+6p+1-q^2

factor

9 p^{2} + 6 p + 1 - q^{2}

(3 p + 1 + q) (3 p + 1 - q)

Solution steps

9 p^{2} + 6 p + 1 - q^{2}

Factor

9 p^{2} + 6 p + 1 : (3 p + 1)^{2}

= (3 p + 1)^{2} - q^{2}

Apply Difference of Two Squares Formula:

x^{2} - y^{2} = (x + y) (x - y)

(3 p + 1)^{2} - q^{2} = ((3 p + 1) + q) ((3 p + 1) - q)

= ((3 p + 1) + q) ((3 p + 1) - q)

Apply rule:

(a) = a

(3 p + 1) = 3 p + 1

= (3 p + 1 + q) (3 p + 1 - q)

5 a + 15

3 x^{4} - 16 x^{3} + 14 x^{2} + 24 x - 9

x < 2 - x

(- \frac{5}{x})^{2}

(3 + - 5) (7 - - 10)

What is factor 9p^2+6p+1-q^2 ?
The solution to factor 9p^2+6p+1-q^2 is (3p+1+q)(3p+1-q)