What are the solutions to the equation x^2-18x-32=0 ?

The solutions to the equation x^2-18x-32=0 are x=9+sqrt(113),x=9-sqrt(113)

Find the zeros of x^2-18x-32=0

The zeros of x^2-18x-32=0 are x=9+sqrt(113),x=9-sqrt(113)

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x^{2} - 18 x - 32 = 0

x = 9 + 113, x = 9 - 113

Decimal Notation

x = 19.63014 \dots, x = - 1.63014 \dots

Solution steps

x^{2} - 18 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot ( - 32 )}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot (- 32) = 2113

x_{1, 2} = \frac{- ( - 18 ) \pm 2 113}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 2 113}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 2 113}{2 \cdot 1}

x = \frac{- ( - 18 ) + 2 113}{2 \cdot 1} : 9 + 113

x = \frac{- ( - 18 ) - 2 113}{2 \cdot 1} : 9 - 113

The solutions to the quadratic equation are:

x = 9 + 113, x = 9 - 113

k^{2} + 8 k + 12 = 0

- 6 x + 5 x^{2} = - 8

x, 5 x^{2} + 5 y^{2} = 0

n, x = \frac{n ( n + 1 )}{2}

4.905 t^{2} - 25.11 t + 11 = 0

What are the solutions to the equation x^2-18x-32=0 ?
The solutions to the equation x^2-18x-32=0 are x=9+sqrt(113),x=9-sqrt(113)
Find the zeros of x^2-18x-32=0
The zeros of x^2-18x-32=0 are x=9+sqrt(113),x=9-sqrt(113)