What are the solutions to the equation 4X^2-12X+9=0 ?

The solutions to the equation 4X^2-12X+9=0 are X= 3/2

Find the zeros of 4X^2-12X+9=0

The zeros of 4X^2-12X+9=0 are X= 3/2

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4 X^{2} - 12 X + 9 = 0

X = \frac{3}{2}

Decimal Notation

X = 1.5

Solution steps

4 X^{2} - 12 X + 9 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 4 \cdot 9}{2 \cdot 4}

(- 12)^{2} - 4 \cdot 4 \cdot 9 = 0

X_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 4}

X = \frac{- ( - 12 )}{2 \cdot 4}

\frac{- ( - 12 )}{2 \cdot 4} = \frac{3}{2}

X = \frac{3}{2}

The solution to the quadratic equation is:

X = \frac{3}{2}

10 = (x + 2) (x - 1)

x^{2} + 6 x + 8 = 2 x^{2} - x

2 x^{2} - 9 x = 7 x - 64

x^{2} - 4 x - 46 = 0

1^{2} + y^{2} = 1 + 8 y

What are the solutions to the equation 4X^2-12X+9=0 ?
The solutions to the equation 4X^2-12X+9=0 are X= 3/2
Find the zeros of 4X^2-12X+9=0
The zeros of 4X^2-12X+9=0 are X= 3/2