What are the solutions to the equation 0=-25x^2+40x-16 ?

The solutions to the equation 0=-25x^2+40x-16 are x= 4/5

Find the zeros of 0=-25x^2+40x-16

The zeros of 0=-25x^2+40x-16 are x= 4/5

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0 = - 25 x^{2} + 40 x - 16

x = \frac{4}{5}

Decimal Notation

x = 0.8

Solution steps

0 = - 25 x^{2} + 40 x - 16

Switch sides

- 25 x^{2} + 40 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 25 ) ( - 16 )}{2 ( - 25 )}

4 0^{2} - 4 (- 25) (- 16) = 0

x_{1, 2} = \frac{- 40 \pm 0}{2 ( - 25 )}

x = \frac{- 40}{2 ( - 25 )}

\frac{- 40}{2 ( - 25 )} = \frac{4}{5}

x = \frac{4}{5}

The solution to the quadratic equation is:

x = \frac{4}{5}

6 x^{2} - 3 x + 4 = 0

x (3 x + 1) = 0

- 7 x^{2} + 3 x = 5 x

x^{2} - 8 x - 25 = - 16

x, 3 x^{2} + 6 x + 2 = 0

What are the solutions to the equation 0=-25x^2+40x-16 ?
The solutions to the equation 0=-25x^2+40x-16 are x= 4/5
Find the zeros of 0=-25x^2+40x-16
The zeros of 0=-25x^2+40x-16 are x= 4/5