What are the solutions to the equation 5(x+3)^2+10=130 ?

The solutions to the equation 5(x+3)^2+10=130 are x=2sqrt(6)-3,x=-2sqrt(6)-3

Find the zeros of 5(x+3)^2+10=130

The zeros of 5(x+3)^2+10=130 are x=2sqrt(6)-3,x=-2sqrt(6)-3

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5 (x + 3)^{2} + 10 = 130

x = 26 - 3, x = - 26 - 3

Decimal Notation

x = 1.89897 \dots, x = - 7.89897 \dots

Solution steps

5 (x + 3)^{2} + 10 = 130

Move

10

to the right side

5 (x + 3)^{2} = 120

Divide both sides by

5

(x + 3)^{2} = 24

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 24 : x = 26 - 3

Solve

x + 3 = - 24 : x = - 26 - 3

The solutions to the quadratic equation are:

x = 26 - 3, x = - 26 - 3

x^{2} = 6 x - 117

x^{2} - 3 x - 54 = 0

xx + 5 x = 24

- 10 x^{2} = 3 x^{2} - 3

2 (s + 1)^{2} - 5 (s + 1) - 3 = 0

What are the solutions to the equation 5(x+3)^2+10=130 ?
The solutions to the equation 5(x+3)^2+10=130 are x=2sqrt(6)-3,x=-2sqrt(6)-3
Find the zeros of 5(x+3)^2+10=130
The zeros of 5(x+3)^2+10=130 are x=2sqrt(6)-3,x=-2sqrt(6)-3