What are the solutions to the equation 14x^2-18x+36=0 ?

The solutions to the equation 14x^2-18x+36=0 are x= 9/14+i(3sqrt(47))/(14),x= 9/14-i(3sqrt(47))/(14)

Find the zeros of 14x^2-18x+36=0

The zeros of 14x^2-18x+36=0 are x= 9/14+i(3sqrt(47))/(14),x= 9/14-i(3sqrt(47))/(14)

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14 x^{2} - 18 x + 36 = 0

x = \frac{9}{14} + i \frac{3 47}{14}, x = \frac{9}{14} - i \frac{3 47}{14}

Solution steps

14 x^{2} - 18 x + 36 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 14 \cdot 36}{2 \cdot 14}

Simplify

(- 18)^{2} - 4 \cdot 14 \cdot 36 : 647 i

x_{1, 2} = \frac{- ( - 18 ) \pm 6 47 i}{2 \cdot 14}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 6 47 i}{2 \cdot 14}, x_{2} = \frac{- ( - 18 ) - 6 47 i}{2 \cdot 14}

x = \frac{- ( - 18 ) + 6 47 i}{2 \cdot 14} : \frac{9}{14} + i \frac{3 47}{14}

x = \frac{- ( - 18 ) - 6 47 i}{2 \cdot 14} : \frac{9}{14} - i \frac{3 47}{14}

The solutions to the quadratic equation are:

x = \frac{9}{14} + i \frac{3 47}{14}, x = \frac{9}{14} - i \frac{3 47}{14}

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What are the solutions to the equation 14x^2-18x+36=0 ?
The solutions to the equation 14x^2-18x+36=0 are x= 9/14+i(3sqrt(47))/(14),x= 9/14-i(3sqrt(47))/(14)
Find the zeros of 14x^2-18x+36=0
The zeros of 14x^2-18x+36=0 are x= 9/14+i(3sqrt(47))/(14),x= 9/14-i(3sqrt(47))/(14)