What are the solutions to the equation (4x-5)^2=-8x+10 ?

The solutions to the equation (4x-5)^2=-8x+10 are x= 5/4 ,x= 3/4

Find the zeros of (4x-5)^2=-8x+10

The zeros of (4x-5)^2=-8x+10 are x= 5/4 ,x= 3/4

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(4 x - 5)^{2} = - 8 x + 10

x = \frac{5}{4}, x = \frac{3}{4}

Decimal Notation

x = 1.25, x = 0.75

Solution steps

(4 x - 5)^{2} = - 8 x + 10

Expand

(4 x - 5)^{2} : 16 x^{2} - 40 x + 25

16 x^{2} - 40 x + 25 = - 8 x + 10

Move

10

to the left side

16 x^{2} - 40 x + 15 = - 8 x

Move

8 x

to the left side

16 x^{2} - 32 x + 15 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 32 ) \pm ( - 32 ) ^{2} - 4 \cdot 16 \cdot 15}{2 \cdot 16}

(- 32)^{2} - 4 \cdot 16 \cdot 15 = 8

x_{1, 2} = \frac{- ( - 32 ) \pm 8}{2 \cdot 16}

Separate the solutions

x_{1} = \frac{- ( - 32 ) + 8}{2 \cdot 16}, x_{2} = \frac{- ( - 32 ) - 8}{2 \cdot 16}

x = \frac{- ( - 32 ) + 8}{2 \cdot 16} : \frac{5}{4}

x = \frac{- ( - 32 ) - 8}{2 \cdot 16} : \frac{3}{4}

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = \frac{3}{4}

8 x^{2} = - 8 x - 1

3 x^{2} - b x = c

(m + 7) (2 m - 1) = 0

x + 5 x^{2} = 0

x^{2} - (- 5) x + 6 = 0

What are the solutions to the equation (4x-5)^2=-8x+10 ?
The solutions to the equation (4x-5)^2=-8x+10 are x= 5/4 ,x= 3/4
Find the zeros of (4x-5)^2=-8x+10
The zeros of (4x-5)^2=-8x+10 are x= 5/4 ,x= 3/4