What are the solutions to the equation x^2+(-15/17)^2=1 ?

The solutions to the equation x^2+(-15/17)^2=1 are x= 8/17 ,x=-8/17

Find the zeros of x^2+(-15/17)^2=1

The zeros of x^2+(-15/17)^2=1 are x= 8/17 ,x=-8/17

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x^{2} + (- \frac{15}{17})^{2} = 1

x = \frac{8}{17}, x = - \frac{8}{17}

Decimal Notation

x = 0.47058 \dots, x = - 0.47058 \dots

Solution steps

x^{2} + (- \frac{15}{17})^{2} = 1

Expand

x^{2} + (- \frac{15}{17})^{2} : x^{2} + \frac{225}{289}

x^{2} + \frac{225}{289} = 1

Move

\frac{225}{289}

to the right side

x^{2} = 1 - \frac{225}{289}

Simplify

1 - \frac{225}{289} : \frac{64}{289}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{64}{289}, x = - \frac{64}{289}

\frac{64}{289} = \frac{8}{17}

- \frac{64}{289} = - \frac{8}{17}

x = \frac{8}{17}, x = - \frac{8}{17}

x, x^{2} + 8 x + 15 = 0

s^{2} = - 16

3 r^{2} = - 48 r

2 x^{2} + 4 x - 2

2 x^{2} + 4 x - 7

What are the solutions to the equation x^2+(-15/17)^2=1 ?
The solutions to the equation x^2+(-15/17)^2=1 are x= 8/17 ,x=-8/17
Find the zeros of x^2+(-15/17)^2=1
The zeros of x^2+(-15/17)^2=1 are x= 8/17 ,x=-8/17