What are the solutions to the equation (x-10)(x-8)=-1 ?

The solutions to the equation (x-10)(x-8)=-1 are x=9

Find the zeros of (x-10)(x-8)=-1

The zeros of (x-10)(x-8)=-1 are x=9

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(x - 10) (x - 8) = - 1

x = 9

Solution steps

(x - 10) (x - 8) = - 1

Expand

(x - 10) (x - 8) : x^{2} - 18 x + 80

x^{2} - 18 x + 80 = - 1

Move

1

to the left side

x^{2} - 18 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 81 = 0

x_{1, 2} = \frac{- ( - 18 ) \pm 0}{2 \cdot 1}

x = \frac{- ( - 18 )}{2 \cdot 1}

\frac{- ( - 18 )}{2 \cdot 1} = 9

x = 9

The solution to the quadratic equation is:

x = 9

2 x (x - 2) = 3

(x - 1)^{2} - 8 x - 8 - 9 = 0

z^{2} - 7 z - 7 = 0

2 z^{2} - 10 z + 12 = 0

(x + 2)^{2} + 6 = 0

What are the solutions to the equation (x-10)(x-8)=-1 ?
The solutions to the equation (x-10)(x-8)=-1 are x=9
Find the zeros of (x-10)(x-8)=-1
The zeros of (x-10)(x-8)=-1 are x=9