What are the solutions to the equation x^2+2x+(-6-3)^2=0 ?

The solutions to the equation x^2+2x+(-6-3)^2=0 are x=-1+4sqrt(5)i,x=-1-4sqrt(5)i

Find the zeros of x^2+2x+(-6-3)^2=0

The zeros of x^2+2x+(-6-3)^2=0 are x=-1+4sqrt(5)i,x=-1-4sqrt(5)i

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x^{2} + 2 x + (- 6 - 3)^{2} = 0

x = - 1 + 45 i, x = - 1 - 45 i

Solution steps

x^{2} + 2 x + (- 6 - 3)^{2} = 0

Expand

x^{2} + 2 x + (- 6 - 3)^{2} : x^{2} + 2 x + 81

x^{2} + 2 x + 81 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot 81}{2 \cdot 1}

Simplify

2^{2} - 4 \cdot 1 \cdot 81 : 85 i

x_{1, 2} = \frac{- 2 \pm 8 5 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 2 + 8 5 i}{2 \cdot 1}, x_{2} = \frac{- 2 - 8 5 i}{2 \cdot 1}

x = \frac{- 2 + 8 5 i}{2 \cdot 1} : - 1 + 45 i

x = \frac{- 2 - 8 5 i}{2 \cdot 1} : - 1 - 45 i

The solutions to the quadratic equation are:

x = - 1 + 45 i, x = - 1 - 45 i

20619 a^{2} - 2411340 a + 72000000 = 0

2 x^{2} + 9 x + 16 = 0

x^{2} - 11 x = 0

x (x + 10) = 2184

j, z = (2 - j) (2 + 3 j)

What are the solutions to the equation x^2+2x+(-6-3)^2=0 ?
The solutions to the equation x^2+2x+(-6-3)^2=0 are x=-1+4sqrt(5)i,x=-1-4sqrt(5)i
Find the zeros of x^2+2x+(-6-3)^2=0
The zeros of x^2+2x+(-6-3)^2=0 are x=-1+4sqrt(5)i,x=-1-4sqrt(5)i