What are the solutions to the equation x(x+10)=2184 ?

The solutions to the equation x(x+10)=2184 are x=42,x=-52

Find the zeros of x(x+10)=2184

The zeros of x(x+10)=2184 are x=42,x=-52

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x (x + 10) = 2184

x = 42, x = - 52

Solution steps

x (x + 10) = 2184

Expand

x (x + 10) : x^{2} + 10 x

x^{2} + 10 x = 2184

Move

2184

to the left side

x^{2} + 10 x - 2184 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 2184 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 2184) = 94

x_{1, 2} = \frac{- 10 \pm 94}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 94}{2 \cdot 1}, x_{2} = \frac{- 10 - 94}{2 \cdot 1}

x = \frac{- 10 + 94}{2 \cdot 1} : 42

x = \frac{- 10 - 94}{2 \cdot 1} : - 52

The solutions to the quadratic equation are:

x = 42, x = - 52

j, z = (2 - j) (2 + 3 j)

x^{2} + 108 = 0

- 2 w^{2} + 12 w + 19 = 0

y^{2} + x = 1, y

y^{2} + 5 y - 1

What are the solutions to the equation x(x+10)=2184 ?
The solutions to the equation x(x+10)=2184 are x=42,x=-52
Find the zeros of x(x+10)=2184
The zeros of x(x+10)=2184 are x=42,x=-52