What are the solutions to the equation completesquare y^2+5y-1 ?

The solutions to the equation completesquare y^2+5y-1 are (y+5/2)^2-29/4

Find the zeros of completesquare y^2+5y-1

The zeros of completesquare y^2+5y-1 are (y+5/2)^2-29/4

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complete the square

y^{2} + 5 y - 1

(y + \frac{5}{2})^{2} - \frac{29}{4}

Solution steps

y^{2} + 5 y - 1

Write

y^{2} + 5 y - 1

in the form:

x^{2} + 2 a x + a^{2}

2 a = 5 : a = \frac{5}{2}

Add and subtract

(\frac{5}{2})^{2}

y^{2} + 5 y - 1 + (\frac{5}{2})^{2} - (\frac{5}{2})^{2}

x^{2} + 2 a x + a^{2} = (x + a)^{2}

y^{2} + 5 y + (\frac{5}{2})^{2} = (y + \frac{5}{2})^{2}

(y + \frac{5}{2})^{2} - 1 - (\frac{5}{2})^{2}

Simplify

(y + \frac{5}{2})^{2} - \frac{29}{4}

x^{2} + 4 x = - 3

- 6 x^{2} + 3 x + 2 = 3

1 = 0.001 x^{2} - 0.612 x + 168

4 x^{2} = 40

3 a^{2} - 11 a + 10 = 0

What are the solutions to the equation completesquare y^2+5y-1 ?
The solutions to the equation completesquare y^2+5y-1 are (y+5/2)^2-29/4
Find the zeros of completesquare y^2+5y-1
The zeros of completesquare y^2+5y-1 are (y+5/2)^2-29/4