What are the solutions to the equation factor x^2+4x=-3 ?

The solutions to the equation factor x^2+4x=-3 are x=-1,x=-3

Find the zeros of factor x^2+4x=-3

The zeros of factor x^2+4x=-3 are x=-1,x=-3

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x^{2} + 4 x = - 3

x = - 1, x = - 3

Solution steps

x^{2} + 4 x = - 3

Move

3

to the left side

x^{2} + 4 x + 3 = 0

Factor

x^{2} + 4 x + 3 : (x + 1) (x + 3)

(x + 1) (x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 1 = 0 or x + 3 = 0

Solve

x + 1 = 0 : x = - 1

Solve

x + 3 = 0 : x = - 3

The solutions to the quadratic equation are:

x = - 1, x = - 3

- 6 x^{2} + 3 x + 2 = 3

1 = 0.001 x^{2} - 0.612 x + 168

4 x^{2} = 40

3 a^{2} - 11 a + 10 = 0

0 = 3 x^{2} - 2 x + 9

What are the solutions to the equation factor x^2+4x=-3 ?
The solutions to the equation factor x^2+4x=-3 are x=-1,x=-3
Find the zeros of factor x^2+4x=-3
The zeros of factor x^2+4x=-3 are x=-1,x=-3