What are the solutions to the equation 12=x^2-2x+1 ?

The solutions to the equation 12=x^2-2x+1 are x=1+2sqrt(3),x=1-2sqrt(3)

Find the zeros of 12=x^2-2x+1

The zeros of 12=x^2-2x+1 are x=1+2sqrt(3),x=1-2sqrt(3)

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12 = x^{2} - 2 x + 1

x = 1 + 23, x = 1 - 23

Decimal

x = 4.46410 \dots, x = - 2.46410 \dots

Solution steps

12 = x^{2} - 2 x + 1

Switch sides

x^{2} - 2 x + 1 = 12

Move

12

to the left side

x^{2} - 2 x - 11 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 11 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 11) = 43

x_{1, 2} = \frac{- ( - 2 ) \pm 4 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 4 3}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 4 3}{2 \cdot 1}

x = \frac{- ( - 2 ) + 4 3}{2 \cdot 1} : 1 + 23

x = \frac{- ( - 2 ) - 4 3}{2 \cdot 1} : 1 - 23

The solutions to the quadratic equation are:

x = 1 + 23, x = 1 - 23

3 (x - 2 + 4) (2 x - 1) = 5 (x + 5) - 2 (x - 3)

0 = \frac{27 - x ^{2}}{2}

y^{2} + y + 1

x, x^{2} - 8 x = - x

x, f (x - 1) = x^{2} + 1

What are the solutions to the equation 12=x^2-2x+1 ?
The solutions to the equation 12=x^2-2x+1 are x=1+2sqrt(3),x=1-2sqrt(3)
Find the zeros of 12=x^2-2x+1
The zeros of 12=x^2-2x+1 are x=1+2sqrt(3),x=1-2sqrt(3)