What are the solutions to the equation solvefor x,x^2-8x=-x ?

The solutions to the equation solvefor x,x^2-8x=-x are x=7,x=0

Find the zeros of solvefor x,x^2-8x=-x

The zeros of solvefor x,x^2-8x=-x are x=7,x=0

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x, x^{2} - 8 x = - x

x = 7, x = 0

Solution steps

x^{2} - 8 x = - x

Move

x

to the left side

x^{2} - 7 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 0 = 7

x_{1, 2} = \frac{- ( - 7 ) \pm 7}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 7}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 7}{2 \cdot 1}

x = \frac{- ( - 7 ) + 7}{2 \cdot 1} : 7

x = \frac{- ( - 7 ) - 7}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

x = 7, x = 0

x, f (x - 1) = x^{2} + 1

5 x^{2} + 12 x - 2 = 0

y^{2} - 6 y + 9 = - 25

3 x^{2} - 2 x + 1

3 (x - 2)^{2} - 8 = 19

What are the solutions to the equation solvefor x,x^2-8x=-x ?
The solutions to the equation solvefor x,x^2-8x=-x are x=7,x=0
Find the zeros of solvefor x,x^2-8x=-x
The zeros of solvefor x,x^2-8x=-x are x=7,x=0