What are the solutions to the equation 4x^2+25=16x ?

The solutions to the equation 4x^2+25=16x are x=2+i 3/2 ,x=2-i 3/2

Find the zeros of 4x^2+25=16x

The zeros of 4x^2+25=16x are x=2+i 3/2 ,x=2-i 3/2

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4 x^{2} + 25 = 16 x

x = 2 + i \frac{3}{2}, x = 2 - i \frac{3}{2}

Solution steps

4 x^{2} + 25 = 16 x

Move

16 x

to the left side

4 x^{2} + 25 - 16 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - 16 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

Simplify

(- 16)^{2} - 4 \cdot 4 \cdot 25 : 12 i

x_{1, 2} = \frac{- ( - 16 ) \pm 12 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 12 i}{2 \cdot 4}, x_{2} = \frac{- ( - 16 ) - 12 i}{2 \cdot 4}

x = \frac{- ( - 16 ) + 12 i}{2 \cdot 4} : 2 + i \frac{3}{2}

x = \frac{- ( - 16 ) - 12 i}{2 \cdot 4} : 2 - i \frac{3}{2}

The solutions to the quadratic equation are:

x = 2 + i \frac{3}{2}, x = 2 - i \frac{3}{2}

C = 3 x^{2} - 200 x + 5250.55

x^{2} - 18 x - 81 = - 161

x^{2} - 10 x + 7

4 d^{2} - d - 3 = - d^{2}

2 x^{2} - x - 10 = 0

What are the solutions to the equation 4x^2+25=16x ?
The solutions to the equation 4x^2+25=16x are x=2+i 3/2 ,x=2-i 3/2
Find the zeros of 4x^2+25=16x
The zeros of 4x^2+25=16x are x=2+i 3/2 ,x=2-i 3/2