What are the solutions to the equation (3p^2+15p)/2 =9 ?

The solutions to the equation (3p^2+15p)/2 =9 are p=1,p=-6

Find the zeros of (3p^2+15p)/2 =9

The zeros of (3p^2+15p)/2 =9 are p=1,p=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{3 p ^{2} + 15 p}{2} = 9

p = 1, p = - 6

Solution steps

\frac{3 p ^{2} + 15 p}{2} = 9

Multiply both sides by

2

3 p^{2} + 15 p = 18

Move

18

to the left side

3 p^{2} + 15 p - 18 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 3 ( - 18 )}{2 \cdot 3}

1 5^{2} - 4 \cdot 3 (- 18) = 21

p_{1, 2} = \frac{- 15 \pm 21}{2 \cdot 3}

Separate the solutions

p_{1} = \frac{- 15 + 21}{2 \cdot 3}, p_{2} = \frac{- 15 - 21}{2 \cdot 3}

p = \frac{- 15 + 21}{2 \cdot 3} : 1

p = \frac{- 15 - 21}{2 \cdot 3} : - 6

The solutions to the quadratic equation are:

p = 1, p = - 6

3 x^{2} - 7 x - 6 = 0

\frac{7}{2} x^{2} - 33.3 x - 33.3 = 0

p^{2} + 6 p + 9 = 0

2730 = - 0.4 x^{2} + 68 x

x, 2 x^{2} - x y - y^{2} = 0

What are the solutions to the equation (3p^2+15p)/2 =9 ?
The solutions to the equation (3p^2+15p)/2 =9 are p=1,p=-6
Find the zeros of (3p^2+15p)/2 =9
The zeros of (3p^2+15p)/2 =9 are p=1,p=-6