What are the solutions to the equation solvefor x,2x^2-xy-y^2=0 ?

The solutions to the equation solvefor x,2x^2-xy-y^2=0 are x=y,x=-y/2

Find the zeros of solvefor x,2x^2-xy-y^2=0

The zeros of solvefor x,2x^2-xy-y^2=0 are x=y,x=-y/2

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solve for

x, 2 x^{2} - x y - y^{2} = 0

x = y, x = - \frac{y}{2}

Solution steps

2 x^{2} - x y - y^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

2 x^{2} - y x - y^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - y ) \pm ( - y ) ^{2} - 4 \cdot 2 ( - y ^{2} )}{2 \cdot 2}

Simplify

(- y)^{2} - 4 \cdot 2 (- y^{2}) : 3 y

x_{1, 2} = \frac{- ( - y ) \pm 3 y}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - y ) + 3 y}{2 \cdot 2}, x_{2} = \frac{- ( - y ) - 3 y}{2 \cdot 2}

x = \frac{- ( - y ) + 3 y}{2 \cdot 2} : y

x = \frac{- ( - y ) - 3 y}{2 \cdot 2} : - \frac{y}{2}

The solutions to the quadratic equation are:

x = y, x = - \frac{y}{2}

7 s^{2} - 21 s = - 14

x, 3 x^{2} + 12 x + 6 = 0

3 x^{2} - 11 x + 2 = 0

(x - 2)^{2} + (x + 1)^{2} = 9

11 r^{2} - 15 r = - 4

What are the solutions to the equation solvefor x,2x^2-xy-y^2=0 ?
The solutions to the equation solvefor x,2x^2-xy-y^2=0 are x=y,x=-y/2
Find the zeros of solvefor x,2x^2-xy-y^2=0
The zeros of solvefor x,2x^2-xy-y^2=0 are x=y,x=-y/2