What are the solutions to the equation 5x^2-36x+7=0 ?

The solutions to the equation 5x^2-36x+7=0 are x=7,x= 1/5

Find the zeros of 5x^2-36x+7=0

The zeros of 5x^2-36x+7=0 are x=7,x= 1/5

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5 x^{2} - 36 x + 7 = 0

x = 7, x = \frac{1}{5}

Decimal Notation

x = 7, x = 0.2

Solution steps

5 x^{2} - 36 x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 36 ) \pm ( - 36 ) ^{2} - 4 \cdot 5 \cdot 7}{2 \cdot 5}

(- 36)^{2} - 4 \cdot 5 \cdot 7 = 34

x_{1, 2} = \frac{- ( - 36 ) \pm 34}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 36 ) + 34}{2 \cdot 5}, x_{2} = \frac{- ( - 36 ) - 34}{2 \cdot 5}

x = \frac{- ( - 36 ) + 34}{2 \cdot 5} : 7

x = \frac{- ( - 36 ) - 34}{2 \cdot 5} : \frac{1}{5}

The solutions to the quadratic equation are:

x = 7, x = \frac{1}{5}

3 x^{2} = 5 mod 7

2 (- 3 x + 5)^{2} - 7 = 1

a, a^{2} = b^{3}

10 0^{2} = 9 6^{2} + x^{2}

- 1.5 x = 0.1 x^{2}

What are the solutions to the equation 5x^2-36x+7=0 ?
The solutions to the equation 5x^2-36x+7=0 are x=7,x= 1/5
Find the zeros of 5x^2-36x+7=0
The zeros of 5x^2-36x+7=0 are x=7,x= 1/5