What are the solutions to the equation solvefor a,a^2+b^2=6ab ?

The solutions to the equation solvefor a,a^2+b^2=6ab are a=(3+2sqrt(2))b,a=(3-2sqrt(2))b

Find the zeros of solvefor a,a^2+b^2=6ab

The zeros of solvefor a,a^2+b^2=6ab are a=(3+2sqrt(2))b,a=(3-2sqrt(2))b

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solve for

a, a^{2} + b^{2} = 6 ab

a = (3 + 22) b, a = (3 - 22) b

Solution steps

a^{2} + b^{2} = 6 ab

Move

6 ab

to the left side

a^{2} + b^{2} - 6 ab = 0

Write in the standard form

a x^{2} + b x + c = 0

a^{2} - 6 ba + b^{2} = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 6 b ) \pm ( - 6 b ) ^{2} - 4 \cdot 1 \cdot b ^{2}}{2 \cdot 1}

Simplify

(- 6 b)^{2} - 4 \cdot 1 \cdot b^{2} : 42 b

a_{1, 2} = \frac{- ( - 6 b ) \pm 4 2 b}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- ( - 6 b ) + 4 2 b}{2 \cdot 1}, a_{2} = \frac{- ( - 6 b ) - 4 2 b}{2 \cdot 1}

a = \frac{- ( - 6 b ) + 4 2 b}{2 \cdot 1} : (3 + 22) b

a = \frac{- ( - 6 b ) - 4 2 b}{2 \cdot 1} : (3 - 22) b

The solutions to the quadratic equation are:

a = (3 + 22) b, a = (3 - 22) b

n^{2} + 6 = 7 n

3 x (2 - x) = 0

4 x^{2} - 16 x = 20

0 = x^{2} + 4 x - 21

1 0^{2} + x^{2} = 1 6^{2}

What are the solutions to the equation solvefor a,a^2+b^2=6ab ?
The solutions to the equation solvefor a,a^2+b^2=6ab are a=(3+2sqrt(2))b,a=(3-2sqrt(2))b
Find the zeros of solvefor a,a^2+b^2=6ab
The zeros of solvefor a,a^2+b^2=6ab are a=(3+2sqrt(2))b,a=(3-2sqrt(2))b