What are the solutions to the equation (2x+4)(x-3)=0 ?

The solutions to the equation (2x+4)(x-3)=0 are x=-2,x=3

Find the zeros of (2x+4)(x-3)=0

The zeros of (2x+4)(x-3)=0 are x=-2,x=3

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(2 x + 4) (x - 3) = 0

x = - 2, x = 3

Solution steps

(2 x + 4) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 4 = 0 or x - 3 = 0

Solve

2 x + 4 = 0 : x = - 2

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = - 2, x = 3

7 x^{2} - x^{2} = 168

x^{2} + 10 x = 2

z^{2} + z - 6 = 0

(2 n - 1) v^{2} - 2 n v + 1 = 0

2 x (x - 8) = 0

What are the solutions to the equation (2x+4)(x-3)=0 ?
The solutions to the equation (2x+4)(x-3)=0 are x=-2,x=3
Find the zeros of (2x+4)(x-3)=0
The zeros of (2x+4)(x-3)=0 are x=-2,x=3