What are the solutions to the equation x^2+10x=2 ?

The solutions to the equation x^2+10x=2 are x=-5+3sqrt(3),x=-5-3sqrt(3)

Find the zeros of x^2+10x=2

The zeros of x^2+10x=2 are x=-5+3sqrt(3),x=-5-3sqrt(3)

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x^{2} + 10 x = 2

x = - 5 + 33, x = - 5 - 33

Solution steps

x^{2} + 10 x = 2

Move

2

to the left side

x^{2} + 10 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot (- 2) = 63

x_{1, 2} = \frac{- 10 \pm 6 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 10 + 6 3}{2 \cdot 1}, x_{2} = \frac{- 10 - 6 3}{2 \cdot 1}

x = \frac{- 10 + 6 3}{2 \cdot 1} : - 5 + 33

x = \frac{- 10 - 6 3}{2 \cdot 1} : - 5 - 33

The solutions to the quadratic equation are:

x = - 5 + 33, x = - 5 - 33

z^{2} + z - 6 = 0

(2 n - 1) v^{2} - 2 n v + 1 = 0

2 x (x - 8) = 0

2 y^{2} = - 40

(x - 2) (2 x - 3) = 0

What are the solutions to the equation x^2+10x=2 ?
The solutions to the equation x^2+10x=2 are x=-5+3sqrt(3),x=-5-3sqrt(3)
Find the zeros of x^2+10x=2
The zeros of x^2+10x=2 are x=-5+3sqrt(3),x=-5-3sqrt(3)