What are the solutions to the equation (x-2)(2x-3)=0 ?

The solutions to the equation (x-2)(2x-3)=0 are x=2,x= 3/2

Find the zeros of (x-2)(2x-3)=0

The zeros of (x-2)(2x-3)=0 are x=2,x= 3/2

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(x - 2) (2 x - 3) = 0

x = 2, x = \frac{3}{2}

Solution steps

(x - 2) (2 x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 2 = 0 or 2 x - 3 = 0

Solve

x - 2 = 0 : x = 2

Solve

2 x - 3 = 0 : x = \frac{3}{2}

The solutions to the quadratic equation are:

x = 2, x = \frac{3}{2}

z^{2} + 0

5 x^{2} - 10 x = 6

9 x^{2} + 54 x + 79 = 0

- 4.9 x^{2} + 205.06 x + 210 = 0

v, r = \frac{v ^{2} p L}{a}

What are the solutions to the equation (x-2)(2x-3)=0 ?
The solutions to the equation (x-2)(2x-3)=0 are x=2,x= 3/2
Find the zeros of (x-2)(2x-3)=0
The zeros of (x-2)(2x-3)=0 are x=2,x= 3/2