What are the solutions to the equation 9x^2+54x+79=0 ?

The solutions to the equation 9x^2+54x+79=0 are x=(-9+sqrt(2))/3 ,x=-(9+sqrt(2))/3

Find the zeros of 9x^2+54x+79=0

The zeros of 9x^2+54x+79=0 are x=(-9+sqrt(2))/3 ,x=-(9+sqrt(2))/3

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9 x^{2} + 54 x + 79 = 0

x = \frac{- 9 + 2}{3}, x = - \frac{9 + 2}{3}

Decimal Notation

x = - 2.52859 \dots, x = - 3.47140 \dots

Solution steps

9 x^{2} + 54 x + 79 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 54 \pm 5 4 ^{2} - 4 \cdot 9 \cdot 79}{2 \cdot 9}

5 4^{2} - 4 \cdot 9 \cdot 79 = 62

x_{1, 2} = \frac{- 54 \pm 6 2}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 54 + 6 2}{2 \cdot 9}, x_{2} = \frac{- 54 - 6 2}{2 \cdot 9}

x = \frac{- 54 + 6 2}{2 \cdot 9} : \frac{- 9 + 2}{3}

x = \frac{- 54 - 6 2}{2 \cdot 9} : - \frac{9 + 2}{3}

The solutions to the quadratic equation are:

x = \frac{- 9 + 2}{3}, x = - \frac{9 + 2}{3}

- 4.9 x^{2} + 205.06 x + 210 = 0

v, r = \frac{v ^{2} p L}{a}

t^{2} + 3 t - 2 = 0

3 x^{2} - 24 x + 54 = 0

0 = 130 - 6 t - 16 t^{2}

What are the solutions to the equation 9x^2+54x+79=0 ?
The solutions to the equation 9x^2+54x+79=0 are x=(-9+sqrt(2))/3 ,x=-(9+sqrt(2))/3
Find the zeros of 9x^2+54x+79=0
The zeros of 9x^2+54x+79=0 are x=(-9+sqrt(2))/3 ,x=-(9+sqrt(2))/3