What are the solutions to the equation 3x^2-24x+54=0 ?

The solutions to the equation 3x^2-24x+54=0 are x=4+sqrt(2)i,x=4-sqrt(2)i

Find the zeros of 3x^2-24x+54=0

The zeros of 3x^2-24x+54=0 are x=4+sqrt(2)i,x=4-sqrt(2)i

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3 x^{2} - 24 x + 54 = 0

x = 4 + 2 i, x = 4 - 2 i

Solution steps

3 x^{2} - 24 x + 54 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 3 \cdot 54}{2 \cdot 3}

Simplify

(- 24)^{2} - 4 \cdot 3 \cdot 54 : 62 i

x_{1, 2} = \frac{- ( - 24 ) \pm 6 2 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 6 2 i}{2 \cdot 3}, x_{2} = \frac{- ( - 24 ) - 6 2 i}{2 \cdot 3}

x = \frac{- ( - 24 ) + 6 2 i}{2 \cdot 3} : 4 + 2 i

x = \frac{- ( - 24 ) - 6 2 i}{2 \cdot 3} : 4 - 2 i

The solutions to the quadratic equation are:

x = 4 + 2 i, x = 4 - 2 i

0 = 130 - 6 t - 16 t^{2}

n^{2} - 4 = 4

w \frac{5 w + 4}{3} = \frac{3 w}{2}

(k + 4)^{2} = 25

x, f (x - 3) = x^{2} + 9 x + 5

What are the solutions to the equation 3x^2-24x+54=0 ?
The solutions to the equation 3x^2-24x+54=0 are x=4+sqrt(2)i,x=4-sqrt(2)i
Find the zeros of 3x^2-24x+54=0
The zeros of 3x^2-24x+54=0 are x=4+sqrt(2)i,x=4-sqrt(2)i