What are the solutions to the equation x^2+4x+64=0 ?

The solutions to the equation x^2+4x+64=0 are x=-2+2sqrt(15)i,x=-2-2sqrt(15)i

Find the zeros of x^2+4x+64=0

The zeros of x^2+4x+64=0 are x=-2+2sqrt(15)i,x=-2-2sqrt(15)i

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x^{2} + 4 x + 64 = 0

x = - 2 + 215 i, x = - 2 - 215 i

Solution steps

x^{2} + 4 x + 64 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

Simplify

4^{2} - 4 \cdot 1 \cdot 64 : 415 i

x_{1, 2} = \frac{- 4 \pm 4 15 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 4 15 i}{2 \cdot 1}, x_{2} = \frac{- 4 - 4 15 i}{2 \cdot 1}

x = \frac{- 4 + 4 15 i}{2 \cdot 1} : - 2 + 215 i

x = \frac{- 4 - 4 15 i}{2 \cdot 1} : - 2 - 215 i

The solutions to the quadratic equation are:

x = - 2 + 215 i, x = - 2 - 215 i

(7 - x) (- 3 - x) + 26 = 0

3 x^{2} - 6 x + 5 = 0

2 x^{2} - 28 = x (x - 3)

2 x^{2} + 7 x - 3

a^{2} - 4 = 3 a

What are the solutions to the equation x^2+4x+64=0 ?
The solutions to the equation x^2+4x+64=0 are x=-2+2sqrt(15)i,x=-2-2sqrt(15)i
Find the zeros of x^2+4x+64=0
The zeros of x^2+4x+64=0 are x=-2+2sqrt(15)i,x=-2-2sqrt(15)i