What are the solutions to the equation (3y+17)^2=50 ?

The solutions to the equation (3y+17)^2=50 are y=(5sqrt(2)-17)/3 ,y=(-5sqrt(2)-17)/3

Find the zeros of (3y+17)^2=50

The zeros of (3y+17)^2=50 are y=(5sqrt(2)-17)/3 ,y=(-5sqrt(2)-17)/3

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(3 y + 17)^{2} = 50

y = \frac{5 2 - 17}{3}, y = \frac{- 5 2 - 17}{3}

Solution steps

(3 y + 17)^{2} = 50

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

3 y + 17 = 50 : y = \frac{5 2 - 17}{3}

Solve

3 y + 17 = - 50 : y = \frac{- 5 2 - 17}{3}

The solutions to the quadratic equation are:

y = \frac{5 2 - 17}{3}, y = \frac{- 5 2 - 17}{3}

w^{2} = 8 (w - 4)

a, a b^{2} + a^{2} b + 3 = ab

4 x^{2} + 20 = 4

2 (x - 1)^{2} - 3 = 0

4 x^{2} = 5 x + 6

What are the solutions to the equation (3y+17)^2=50 ?
The solutions to the equation (3y+17)^2=50 are y=(5sqrt(2)-17)/3 ,y=(-5sqrt(2)-17)/3
Find the zeros of (3y+17)^2=50
The zeros of (3y+17)^2=50 are y=(5sqrt(2)-17)/3 ,y=(-5sqrt(2)-17)/3