What are the solutions to the equation 2(x-1)^2-3=0 ?

The solutions to the equation 2(x-1)^2-3=0 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1

Find the zeros of 2(x-1)^2-3=0

The zeros of 2(x-1)^2-3=0 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1

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2 (x - 1)^{2} - 3 = 0

x = \frac{3}{2} + 1, x = - \frac{3}{2} + 1

Solution steps

2 (x - 1)^{2} - 3 = 0

Move

3

to the right side

2 (x - 1)^{2} = 3

Divide both sides by

2

(x - 1)^{2} = \frac{3}{2}

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 1 = \frac{3}{2} : x = \frac{3}{2} + 1

Solve

x - 1 = - \frac{3}{2} : x = - \frac{3}{2} + 1

The solutions to the quadratic equation are:

x = \frac{3}{2} + 1, x = - \frac{3}{2} + 1

4 x^{2} = 5 x + 6

l (h) = - 0.032 h^{2} + 0.3 h + 1

(z + 1)^{2} = - 36

12 z^{2} - 17 z + 6 = 0

v, E c = \frac{m v ^{2}}{2}

What are the solutions to the equation 2(x-1)^2-3=0 ?
The solutions to the equation 2(x-1)^2-3=0 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1
Find the zeros of 2(x-1)^2-3=0
The zeros of 2(x-1)^2-3=0 are x=sqrt(3/2)+1,x=-sqrt(3/2)+1