What are the solutions to the equation (z+1)^2=-36 ?

The solutions to the equation (z+1)^2=-36 are z=6i-1,z=-6i-1

Find the zeros of (z+1)^2=-36

The zeros of (z+1)^2=-36 are z=6i-1,z=-6i-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(z + 1)^{2} = - 36

z = 6 i - 1, z = - 6 i - 1

Solution steps

(z + 1)^{2} = - 36

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

z + 1 = - 36 : z = 6 i - 1

Solve

z + 1 = - - 36 : z = - 6 i - 1

The solutions to the quadratic equation are:

z = 6 i - 1, z = - 6 i - 1

12 z^{2} - 17 z + 6 = 0

v, E c = \frac{m v ^{2}}{2}

z^{2} - \frac{3}{4} z = - 80

x^{1} + 5 x^{2} = 7

25 y^{2} - 25 y + 6 = 0

What are the solutions to the equation (z+1)^2=-36 ?
The solutions to the equation (z+1)^2=-36 are z=6i-1,z=-6i-1
Find the zeros of (z+1)^2=-36
The zeros of (z+1)^2=-36 are z=6i-1,z=-6i-1