What are the solutions to the equation x^1+5x^2=7 ?

The solutions to the equation x^1+5x^2=7 are x=(-1+sqrt(141))/(10),x=(-1-sqrt(141))/(10)

Find the zeros of x^1+5x^2=7

The zeros of x^1+5x^2=7 are x=(-1+sqrt(141))/(10),x=(-1-sqrt(141))/(10)

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x^{1} + 5 x^{2} = 7

x = \frac{- 1 + 141}{10}, x = \frac{- 1 - 141}{10}

Decimal Notation

x = 1.08743 \dots, x = - 1.28743 \dots

Solution steps

x^{1} + 5 x^{2} = 7

Refine

x + 5 x^{2} = 7

Move

7

to the left side

x + 5 x^{2} - 7 = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} + x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 5 ( - 7 )}{2 \cdot 5}

1^{2} - 4 \cdot 5 (- 7) = 141

x_{1, 2} = \frac{- 1 \pm 141}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 1 + 141}{2 \cdot 5}, x_{2} = \frac{- 1 - 141}{2 \cdot 5}

x = \frac{- 1 + 141}{2 \cdot 5} : \frac{- 1 + 141}{10}

x = \frac{- 1 - 141}{2 \cdot 5} : \frac{- 1 - 141}{10}

The solutions to the quadratic equation are:

x = \frac{- 1 + 141}{10}, x = \frac{- 1 - 141}{10}

25 y^{2} - 25 y + 6 = 0

2 x^{2} - x = \frac{1}{2}

5 q^{2} = 18 q + 8

x^{2} + 7 x + 19 = 0

2 (x - 6)^{2} = 98

What are the solutions to the equation x^1+5x^2=7 ?
The solutions to the equation x^1+5x^2=7 are x=(-1+sqrt(141))/(10),x=(-1-sqrt(141))/(10)
Find the zeros of x^1+5x^2=7
The zeros of x^1+5x^2=7 are x=(-1+sqrt(141))/(10),x=(-1-sqrt(141))/(10)