What are the solutions to the equation m^2+6m+7=0 ?

The solutions to the equation m^2+6m+7=0 are m=-3+sqrt(2),m=-3-sqrt(2)

Find the zeros of m^2+6m+7=0

The zeros of m^2+6m+7=0 are m=-3+sqrt(2),m=-3-sqrt(2)

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m^{2} + 6 m + 7 = 0

m = - 3 + 2, m = - 3 - 2

Solution steps

m^{2} + 6 m + 7 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 7 = 22

m_{1, 2} = \frac{- 6 \pm 2 2}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- 6 + 2 2}{2 \cdot 1}, m_{2} = \frac{- 6 - 2 2}{2 \cdot 1}

m = \frac{- 6 + 2 2}{2 \cdot 1} : - 3 + 2

m = \frac{- 6 - 2 2}{2 \cdot 1} : - 3 - 2

The solutions to the quadratic equation are:

m = - 3 + 2, m = - 3 - 2

x, 9 x^{2} + 4 y^{2} - 12 z = 0

20 x^{2} + 2740 x - 112000 = 0

x, r = \frac{k x ^{2}}{y}

4 x^{2} = x - 2

5 y^{2} - 28 y + 15 = 0

What are the solutions to the equation m^2+6m+7=0 ?
The solutions to the equation m^2+6m+7=0 are m=-3+sqrt(2),m=-3-sqrt(2)
Find the zeros of m^2+6m+7=0
The zeros of m^2+6m+7=0 are m=-3+sqrt(2),m=-3-sqrt(2)