What are the solutions to the equation 2-x=2-(x-1)^2 ?

The solutions to the equation 2-x=2-(x-1)^2 are x=(3-sqrt(5))/2 ,x=(3+sqrt(5))/2

Find the zeros of 2-x=2-(x-1)^2

The zeros of 2-x=2-(x-1)^2 are x=(3-sqrt(5))/2 ,x=(3+sqrt(5))/2

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2 - x = 2 - (x - 1)^{2}

x = \frac{3 - 5}{2}, x = \frac{3 + 5}{2}

Solution steps

2 - x = 2 - (x - 1)^{2}

Expand

2 - (x - 1)^{2} : - x^{2} + 2 x + 1

2 - x = - x^{2} + 2 x + 1

Switch sides

- x^{2} + 2 x + 1 = 2 - x

Move

x

to the left side

- x^{2} + 3 x + 1 = 2

Move

2

to the left side

- x^{2} + 3 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) ( - 1 )}{2 ( - 1 )}

3^{2} - 4 (- 1) (- 1) = 5

x_{1, 2} = \frac{- 3 \pm 5}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 5}{2 ( - 1 )}, x_{2} = \frac{- 3 - 5}{2 ( - 1 )}

x = \frac{- 3 + 5}{2 ( - 1 )} : \frac{3 - 5}{2}

x = \frac{- 3 - 5}{2 ( - 1 )} : \frac{3 + 5}{2}

The solutions to the quadratic equation are:

x = \frac{3 - 5}{2}, x = \frac{3 + 5}{2}

(x - 4) (x - 1) = 28

x^{2} - 3.5 x - 15 = 0

3 g^{2} - 12 g = - 4

d^{2} = 45

66 x^{2} - 55 x = 0

What are the solutions to the equation 2-x=2-(x-1)^2 ?
The solutions to the equation 2-x=2-(x-1)^2 are x=(3-sqrt(5))/2 ,x=(3+sqrt(5))/2
Find the zeros of 2-x=2-(x-1)^2
The zeros of 2-x=2-(x-1)^2 are x=(3-sqrt(5))/2 ,x=(3+sqrt(5))/2