What are the solutions to the equation (x+1)^2=13 ?

The solutions to the equation (x+1)^2=13 are x=sqrt(13)-1,x=-sqrt(13)-1

Find the zeros of (x+1)^2=13

The zeros of (x+1)^2=13 are x=sqrt(13)-1,x=-sqrt(13)-1

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(x + 1)^{2} = 13

x = 13 - 1, x = - 13 - 1

Solution steps

(x + 1)^{2} = 13

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = 13 : x = 13 - 1

Solve

x + 1 = - 13 : x = - 13 - 1

The solutions to the quadratic equation are:

x = 13 - 1, x = - 13 - 1

(x + 1)^{2} = 15

2 = 3 x^{2} - x + 2

x^{2} - 2.459 x + 1.5 = 0

2 x^{2} - 6 x + 1 = 0

x^{2} - (3 m - 2) x + (m^{2} - 1) = 0

What are the solutions to the equation (x+1)^2=13 ?
The solutions to the equation (x+1)^2=13 are x=sqrt(13)-1,x=-sqrt(13)-1
Find the zeros of (x+1)^2=13
The zeros of (x+1)^2=13 are x=sqrt(13)-1,x=-sqrt(13)-1