What are the solutions to the equation 3x^2-12x+14=0 ?

The solutions to the equation 3x^2-12x+14=0 are x=2+isqrt(2/3),x=2-isqrt(2/3)

Find the zeros of 3x^2-12x+14=0

The zeros of 3x^2-12x+14=0 are x=2+isqrt(2/3),x=2-isqrt(2/3)

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3 x^{2} - 12 x + 14 = 0

x = 2 + i \frac{2}{3}, x = 2 - i \frac{2}{3}

Solution steps

3 x^{2} - 12 x + 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 3 \cdot 14}{2 \cdot 3}

Simplify

(- 12)^{2} - 4 \cdot 3 \cdot 14 : 26 i

x_{1, 2} = \frac{- ( - 12 ) \pm 2 6 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 2 6 i}{2 \cdot 3}, x_{2} = \frac{- ( - 12 ) - 2 6 i}{2 \cdot 3}

x = \frac{- ( - 12 ) + 2 6 i}{2 \cdot 3} : 2 + i \frac{2}{3}

x = \frac{- ( - 12 ) - 2 6 i}{2 \cdot 3} : 2 - i \frac{2}{3}

The solutions to the quadratic equation are:

x = 2 + i \frac{2}{3}, x = 2 - i \frac{2}{3}

0 = 0.5 x^{2} - 10 x + 100

- x^{2} + 5 x + 10 = 0

x^{2} + 9 x + 90 = 0

- \frac{2}{3} x^{2} = 0

2 a^{2} + 17 a + 30 = 0

What are the solutions to the equation 3x^2-12x+14=0 ?
The solutions to the equation 3x^2-12x+14=0 are x=2+isqrt(2/3),x=2-isqrt(2/3)
Find the zeros of 3x^2-12x+14=0
The zeros of 3x^2-12x+14=0 are x=2+isqrt(2/3),x=2-isqrt(2/3)